CHEMICAL REACTIONS AND EQUATIONS
1. IN A CHEMICAL REACTION, SUBSTANCES CALLED THE REACTIONS ARE CONVERTED INTO SUBSTANCES CALLED PRODUCTS.
2. CHEMICALS REACT TO BECOME MORE STABLE.
3. CHEMICAL REACTIONS ARE REPRESENTED BY CHEMICAL EQUATIONS THAT ARE SHORTHAND SENTENCES. THEY ARE MADE UP OF THE FOLLOWING:
A. SYMBOLS = ELEMENTS EX. CO COBALT
SYMBOLS REPRESENT ATOMS
B. FORMULAS = 2 OR MORE ATOMS COMBINED EX. O2
THIS IS NO LONGER AND ATOM IT IS 2 ATOMS
COMBINED FORMING A MOLECULE
ANOTHER EX. CO THIS IS A MOLECULE OF CARBON MONOXIDE.
TWO ATOMS COMBINED MAKES A MOLECULE
C. 2 Co = 2 ATOMS OF COBALT. THE 2 IS THE COEFFICIENT
AND TELLS HOW MANY ATOMS OR MOLECULES ARE THERE.
D. 02 = 1 MOLECULE OF OXYGEN. THE 2 IS A SUBSCRIPT AND
TELLS HOW MANY ATOMS OR MOLECULES ARE THERE.
E. + = REACTS WITH ON REACTANTS SIDE OR AND ON PRODUCTS
SIDE
F. → OR = MEANS TO FORM
REACTANTS PRODUCTS
EX. 2 Ca + 02 → 2Ca0
COEFFICIENT SUBSCRIPT
2 ATOMS OF CALCIUM REACTS WITH 1 MOLECULE OF OXYGEN
TO FORM 2 MOLECULES OF CALCIUM OXIDE
TYPES OF CHEMICAL REACTIONS
1. THERE ARE MANY TYPES OF CHEMICAL REACTIONS.
HOWEVER MOST REACTIONS FALL INTO 4 BASIC TYPES.
A. DIRECT COMBINATION A + B → AB
2 Na + C12 → 2 NaCl
B. DECOMPOSITION AB A + B
2
H2O
→ 2 H
+ O![]()
C. SINGLE REPLACEMENT A + BX → AX + B
Zn +
2HCl → ZnCl2
+ H2
D. DOUBLE REPLACEMENT AX + BY → BX + AY
CaCO3 + 2 HCL H2CO3 + CACl2
BALANCING EQUATIONS
1. WHEN CHEMICALS REACT THERE HAS TO BE AS MANY
ATOMS OF AN ELEMENT ON THE REACTANT AND PRODUCT
SIDE OF AN EQUATION. (CONSERVATION OF MATTER)
2. TO BALANCE AN EQUATION YOU CAN’T CHANGE THE
NUMBERS WITHIN A MOLECULE. (H2O). THE 2 CAN’T
CHANGE. ELECTRONS HAVE REACHED THE OCTET RULE.
THIS IS STABLE AND WON’T CHANGE. YOU CHANGE THE
NUMBERS IN FRONT OF THE MOLECULE CALLED THE
COEFFICIENT. THIS CHANGES THE NUMBER OF
MOLECULES BUT NOT THE STABLE MOLECULE ITSELF.
3. THE PROBLEM MOST STUDENTS HAVE IS
UNDERSTANDING WHAT THE SYMBOLS MEAN.
A. 2A12 (SO4) 3 MEANS THERE ARE 2
MOLECULES WITH 2 Al IN EACH MAKING A TOTAL OF 4
Al. IT MEANS THERE ARE 3 SO4 POLYATOMIC IONS.
THIS MAKES 6 S AND 24 O IN THE TWO MOLECULES.
4. WHEN BALANCING START WITH THE SIMPLEST
COMBINATION FIRST.
CH4 + O2 → CO2 + H2O
DON’T START WITH THE OXYGEN. IT HAS THREE
PLACES TO BALANCE AT ONCE.
5. WHEN THE NUMBERS GET COMPLEX, USE FRACTIONS
AND THE MULTIPLY BY A SMALL WHOLE NUMBER TO
ELIMINATE THE FRACTION.
Al + O2 → Al2O3
2 Al + 1 ½ O2 → Al203
MULTIPLY BY 2
4 Al + 3 O2 → 2Al203
DETERMINGING IF SINGLE REPLACEMENT REACTIONS WILL OCCUR
DETERMINING IF A DOUBLE REPLACEMENT REACTION WILL OCCUR
AND PRECIPATATES OUT OF SOLUTION
EX.
THIS REACTS BECAUSE THE GAS IS NOT REMAINING AS IONS
Ca(NO3)2 + 2 HCl = 2 HNO3 + CaCl2
THIS DOES NOT REACT BECAUSE AFTER LOOKING ON THE SOLUBILITY CHART BOTH PRODUCTS ARE SOLUABLE AND REMAIN AS IONS.
Cu(OH)2 + 2 HC2H3O2 = 2 H2O + Cu(C2H3O2)2
YES THIS REACTS BECAUSE WATER WAS FORMED NO LONGER REMAINGING AS IONS.
NET IONIC EQUATIONS
IN DOUBLE REPLACEMENT REACTIONS WHERE A PRECIPITATE OCCURS WE WOULD WRITE THE EQUATION AS FOLLOWS:
2NaOH (aq) + CuCl2(aq) = 2 NaCl(aq) + Cu(OH)2(s)
THIS SHOWS THAT THE REACTION OCCURS BUT IT DOES NOT FULLY EXPLAIN WHAT HAPPENED. TO SHOW THIS WE WRITE IT IN AN IONIC EQUATION FORM WHERE ALL AQUEOUS COMPOUNDS SHOW UP AS IONS IN SOLUTION BECAUSE THAT IS WHAT THEY REALLY ARE.
IONIC EQUATION:
2 Na+1(aq) + 2 OH-1(aq) + Cu+2 (aq) + 2Cl-1(aq)
= 2 Na+1 (aq) + 2 Cl-1(aq) + Cu(OH)2(s)
NOTICE IN THIS REACTION Na AND Cl REMAINED IONS ON BOTH THE REACTANTS AND PRODUCTS SIDE. SO, NOTHING CHEMICALLY HAPPENED TO THEM. THEY ARE CALLED SPECTATOR IONS BECAUSE OF THAT. TO MAKE A NET IONIC EQUATION YOU CROSS OUT THE SPECTATOR IONS ON BOTH SIDES OF THE EQUATION.
2 Na+1(aq) + 2 OH-1(aq) + Cu+2 (aq) + 2Cl-1(aq)
= 2 Na+1 (aq) + 2 Cl-1(aq) + Cu(OH)2(s)
THIS ELIMINATES THE 2 Na+2 IONS ON BOTH SIDES AND THE Cl-1 IONS ON BOTH SIDES LEAVING THE FOLLOWING NET IONIC EQUATION:
2OH-1 (aq) = Cu+2(aq) = Cu(OH)2(s)